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I need to make a bar coding by using the numbers to hide the letters . . .

2006-10-28 20:17:31 · 5 answers · asked by joey_manuel54 1 in Science & Mathematics Mathematics

5 answers

F,G,I,J,K,N,O

2006-10-28 20:29:56 · answer #1 · answered by Rim 6 · 0 0

There are a TRUCKLOAD of letter substitution ciphers. The simplest is to assign numbers to the letters in the order they show up in the alphabet, e.g., 5 for E, 12 for L, etc.

To make it a trifle bit more challenging, you can reverse the order, e.g., 1 for Z, 2 for Y, etc.

Another option is to map the letters from the phone keypad, e.g., 32 for E, 53 for L, 61 for M, and again, reversal of the two digits would make it more challenging.

Another approach is to use a rolling cipher, based on a keyphrase, such that each successive letter in the plain text is ciphered with a substitution set that starts with a different value based on the keyphrase, say 15926, which are some digits of pi.

In this case, the first letter would use a cipher where A=1, the second letter would use a cipher where A=5, etc.

Good luck, sounds like a lot of fun.

2006-10-28 20:31:21 · answer #2 · answered by arbiter007 6 · 0 0

Why don't you be simplistic about it, as in 1=E, 2=L, 3=M, 4=H, 5=P? This is almost unlikely to be decoded, since the numbers do not relate to anything besides the scale you used in the first place. You can also use number ciphering, as in 1=A, 2=B, 3=C, etc.; but, that can easily be figured out and decoded.

Hope that helps.

2006-10-28 20:30:02 · answer #3 · answered by hotstepper2100 3 · 0 0

just put the alphabet with the numbers from 1 to 26....etc... easy!
A - 1
B - 2
C - 3
D - 4
E - 5

2006-10-28 20:27:56 · answer #4 · answered by MaggieO 4 · 0 0

as in A-1 b-2 c-3???

lazy butt!

2006-10-28 20:25:55 · answer #5 · answered by Anonymous · 0 0

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