2006-10-28 18:58:42 · 4 answers · asked by ssshhh 3 in Science & Mathematics ➔ Physics
Yes, since you need half the force to give the same stretch.
Th
2006-10-28 19:47:06 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
It doesn't change. Imagine a long spring of length L. A force deflectis it s = F/k. Both the force and the displacement are uniformly distributed along the spring. At the haflway pont, L/2, the force is F/2 and the deflection s/2. Lock the spring at that point, cut away the free half. Now you have a spring of length L/2; its deflection is s/2 from a force of F/2, giving the same spring constant k.
2006-10-28 20:06:58 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
Same as before (spring constant is dependent on material and inter molecular blah blah)
If you arrange both in parallel etc, then maybe first answer.
2006-10-28 19:50:09 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Hooke's Law F=k*Dx
F=k*Dx/2
Solve for k=2F/Dx
so only half as much
2006-10-28 19:10:01 · answer #4 · answered by may 1 · 0⤊ 0⤋