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I have a wire closed at both ends and tuning fork of 450 Hz.
My question is -
I think resonance frequency is that when the frequency of the wire become equal to that of tuning fork. but if I change the mass/density of the wire than will the resonance frequency change?

if it is so but the frequency of tuning fork is still 450 Hz then how can it change

If it is not so then what are thee things which changes with the change of mass and how can we calculate them

2006-10-28 17:54:16 · 4 answers · asked by Sanskar 1 in Science & Mathematics Physics

4 answers

Resonant frequency is calculated with the formula:

f = (1/2L)*root(T/mu)

where L is the wire length, T is the tension and mu is the mass per unit length. So, if you change any of these variables, the resonant frequency will change. The tuning fork will remain unchanged. That's why they use it for tuning......!

2006-10-28 18:14:04 · answer #1 · answered by Steve 7 · 0 0

Noise measurements were carried out in the Cologne area (Germany), and the resonance frequency of each site was estimated from the main peak in the spectral ratio between the horizontal and vertical component. For 32 of these sites, the thickness of the sedimentary cover was known from boreholes, and a clear correlation between resonance frequency and sediment thickness was observed. A formula that correlates cover thickness with frequency of the main peak in the horizontal-to-vertical spectral ratio was derived. In addition, a best-fitting shear-wave-velocity distribution with depth, vs(z), as well as a relationship between average shear-wave velocity s and thickness of the sedimentary cover, was calculated. By using all of the noise measurements and applying the derived relationships, we obtained a subsoil classification for the Cologne area.

2006-10-28 17:57:32 · answer #2 · answered by C.J. W 3 · 0 0

http://en.wikipedia.org/wiki/Resonance#Quantum_field_theory

2006-10-28 18:00:27 · answer #3 · answered by sllyjo 5 · 0 0

Thanks, I get what I was finding.

2016-05-22 04:41:00 · answer #4 · answered by Anonymous · 0 0

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