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A man with $80,000 decides to deversify his investments by placing $20,000 in an account that earns 6.3% compounded continuously and $30,0000 in an account that earns 7.3% compounded annually.

2006-10-28 15:56:06 · 4 answers · asked by Carolyn S 1 in Science & Mathematics Mathematics

4 answers

on the 23rd compounding, the 20k/6.3 acct would go to 81,525.80

on the 14th compounding, the 30k/7.3 acct would go to 80,448.39

if you meant, how long would it take the 50,000 in the two accounts to grow to 80,000, then on the 8th compounding, the total would go to 85,319.05

2006-10-28 16:01:17 · answer #1 · answered by Anonymous · 0 0

Assuming you really mean $20,000 and $30,000 growing to $80,000, the answer is:
It will never exactly equal $80,000, but will cross $80,000 after seven years.

The formula, with T in years, is
total = ($20000 * e^(6.3% * T)) + ($30000*(107.3%)^int(T))

At T = 6.9999 years, the total is $76869.64
At T = 7 years, the total jumps to $80212.11

2006-10-28 16:30:52 · answer #2 · answered by or_try_this 3 · 0 0

First learn how to ask a question
and make it clear for urself b4 asking some question

2006-10-28 16:02:08 · answer #3 · answered by abcdefg 5 · 0 0

investment 1
80,000=20,000(1+63/1000)^n
80,000/20,000=(1063/1000)^n
log4=n(log1063-log1000)
n=log4/[log1063-log1000]

investment 2
80,000=30,000(1+73/1000)^n
80,000/30,000=(1073/1000)^n
log(8/3)=n(log1073-log1000)
n=log(8/3)/[log1073-log1000]

2006-10-28 16:33:41 · answer #4 · answered by raj 7 · 0 0

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