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A right triangle has angles, 37, 90 and 53. How do you find the three sides of the triangle? (What trigonometric functions do I use?)

2006-10-28 15:39:49 · 14 answers · asked by michaelazerrad 1 in Science & Mathematics Mathematics

14 answers

Then it can nnot be solved. You can have only parametric representations

say the hypotenous is x

other two sides will be

x sin 37 and x cos 37

so sides shall be

( x sin 37, x cos 37, x)

ALl the triangles are similar

2006-10-28 15:45:10 · answer #1 · answered by Mein Hoon Na 7 · 1 0

The responses you've received so far are all basically correct.
However, the following information may be helpful to you.

The particular angles you mention are (to the nearest degree) the angles of the famous 3-4-5 right triangle.

As others have pointed out, any triangle of the same SHAPE will have those same angles. So the actual triangle could be 6-8-10, or 4.5-6-7.5, or 18-24-30. But all of these would be referred to as "3-4-5 right triangles," meaning that their sides are in those proportions.

2006-10-28 16:10:08 · answer #2 · answered by actuator 5 · 0 0

There's no way to find the actual side lengths, but you can find them in relation to one another.

For example, let the hypoteneuse have length C.
The cosine of 37 is one of the sides (call it A) over C:
cos(37) = A/C ──►A = C*cos(37)
The sine of 37 is the other side (call it B) over C:
sin(37) = B/C ──► B = C*sin(37)

If you look at the angle 53 and you will find:
A = C*sin(53)
B = C*cos(53)

2006-10-28 15:49:45 · answer #3 · answered by Anonymous · 1 0

The minimum information needed to define a triangle is:
2 angles and
1 side length.

having all 3 angles is redundant and doesnt help you, because the triangle could be of any size, and the angles would be the same.

2006-10-28 15:49:03 · answer #4 · answered by brian-upstairs 3 · 1 0

No can do. A triangle will be defined by any 3 of its 6 elements, except that one of the 3 elements has to be a side.

2006-10-28 15:50:45 · answer #5 · answered by Steve 7 · 0 0

You can't find out the lenghts of the sides without at least one side. There are an infinite amount of triangles with those angles.

2006-10-28 15:50:51 · answer #6 · answered by Buzlite 2 · 0 0

You must know at least one side. Otherwise, the given angles will only yield an infinite number of triangles.

2006-10-28 15:59:52 · answer #7 · answered by Rhinorm 2 · 0 0

The angles can give you the ratio of the sides but not the actual sides. You need at least one side so you have somewhere to start

2006-10-28 16:05:12 · answer #8 · answered by maggie_at0303 3 · 0 0

By the sine rule
a/sinA = b/sinB = c/sinC

so a : b : c = sinA : sinB : sinC
= sin37° : sin90° : sin53°
≈0.602 : 1 : 0.800
≈ 6 : 10 : 8
= 3 : 5 : 4 (Of course we all know the famous 3.4.5 triangle, don't we!)

2006-10-28 18:26:49 · answer #9 · answered by Wal C 6 · 1 0

sin, cos, tan give you the ratios of the sides.
sin = opposite/hypotenuse, cos = adjacent/hypotenuse
tan = opposite/adjacent
with the ratios you can figure length of 2 sides, and pythagoras the third

2006-10-28 15:44:12 · answer #10 · answered by Finite 2 · 0 0

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