What happens if there is a pulley and a monkey is hanging from one side of the rope while an equal immobile mass is hanging from the other end of the rope and suddenly the monkey starts crawling up the rope? Does he go up or down? The mass is moving upwards but is putting a force downwards. The whole equilibrium is messed up...it isn't as easy as it seems.
2006-10-28 15:20:23 · 7 answers · asked by Carrot, the Peanut 1 in Science & Mathematics ➔ Physics
Sorry if I wasn't too clear for some. There is a pulley with a rope through it and hanging from one side there is a monkey and on the other side is a mass.
Thanks Steve! Great answer...you must be a professor or something. I get the thing about the mass but what is it you are saying about the speed and acceleration???
2006-10-28 15:39:47 · update #1
Great...it was only F = ma..(duh)
However, what would happen if the mass were less than the monkey's mass but at some position where equilibrium is still achieved (lower down)...and then the monkey starts crawling upwards. Up or down now?
2006-10-28 15:51:05 · update #2
Not so hard if you just draw a free body diagram. Forget about the weight of the mass and the monkey. They cancel each other out all the time. As soon as the monkey starts to climb the mass will follow the same motion pattern as the monkey because the net tension in the rope will be increased by exactly the amount demanded by the monkey's acceleration.
The only caveat to all this is that the monkey must move twice as fast relative to the rope as his speed towards the pulley.
2006-10-28 15:33:23 · answer #1 · answered by Steve 7 · 1⤊ 0⤋
When the monkey started to climb he would increase the tension in the rope. This would cause the weight to accelerate upwards towards the pulley. As the weight moved up, so some of the rope would move over the pulley onto the monkey's side. This would increase the mass of the rope on the monkey's side, and hence the total mass on the monkey's side. As a result, the weight would continue to accelerate upwards until it jammed in the pulley.
2006-10-28 17:58:22 · answer #2 · answered by Stewart H 4 · 0⤊ 0⤋
Any acceleration by the monkey, due to the monkey pulling on the rope, would be matched by an equal acceleration by the mass, since the force at each end of the rope must be the same. In other words, both the mass and the monkey would move upwards.
That is, of course, assuming a massless and frictionless rope and pulley. If they have real properties, then the equations for forces and acceleration must take those into account.
2006-10-28 15:46:42 · answer #3 · answered by or_try_this 3 · 0⤊ 0⤋
If the mass is immobile, it doesn't move. If the monkey climbs up the rope then he goes up.
If the mass can move then the monkey will go down because the extra force of his pulling on the rope will throw the balance off.
2006-10-28 15:27:51 · answer #4 · answered by dantheman_028 4 · 0⤊ 0⤋
Couldn't it release the rope? The weight of the mirror will pull it down once the weight of the monkey is not the counter weight?
2016-05-22 04:25:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
the monkey is going up! i know that his movement does not change the equillibrium.
2006-10-28 15:30:15 · answer #6 · answered by cowboybabeeup 4 · 0⤊ 0⤋
extremely tough stuff. try searching at a search engine. just that could help!
2014-11-06 16:25:16 · answer #7 · answered by Anonymous · 0⤊ 0⤋