isosceles means the triangle has two sides of equal length. in the general case, it is not a right triangle.
the width (base) is the third side, the height is a line bisecting the angle opposite the width. it bisects the width and makes right angles with it.
so you end up with two smaller right triangles. the legs are the given height and half of the width. use pythagorean theorem to find length of hypotenuse of this smaller triangle.
s = length of isosceles side = sqrt(height^2 + (width/2)^2)
2006-10-28 13:54:34
·
answer #1
·
answered by Anonymous
·
1⤊
0⤋
In an isosceles precise triangle the two equivalent factors might desire to be the legs, through fact the hypotenuse is often the longest facet in a precise triangle. enable x be the size of a leg. Then, by potential of Pythagoras, the size of the hypotenuse is: c = ?(x² + x²) = ?(2x²) = (?2) x yet, you're informed that c is 4 cm. longer than x: c = x + 4 (?2) x = x + 4 ... substituted for c (?2)x - x = 4 ... upload -x to the two factors (?2 - a million)x = 4 .... component on the left x = 4/(?2 - a million) .... divide the two factors by potential of (?2 - a million) So, the respond is 4/(?2 - a million) centimeters.
2016-12-28 07:25:59
·
answer #2
·
answered by ? 3
·
0⤊
0⤋
Drop a line from the top vertex to the base. You will have a triangle with a 90 degree angle. Now use the Pythagorean theorem to solve for the hypotenuse of the new triangle. The hypotenuse is the square root of the height squared plus the 1/2 the base squared. The hypotenuse of the new triangle is the side of the ososceles.
2006-10-28 13:44:41
·
answer #3
·
answered by Gene 7
·
0⤊
1⤋
the height and 1/2 of the base as two sides of a right triangle.
2006-10-28 13:40:36
·
answer #4
·
answered by arbiter007 6
·
0⤊
1⤋
sqrt((width/2)^2 + height^2) = length of the sides by pythagoras
2006-10-28 13:43:55
·
answer #5
·
answered by turkeyphant 3
·
0⤊
0⤋
as above.
2006-10-28 13:46:00
·
answer #6
·
answered by B T 3
·
0⤊
1⤋