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A descent vehicle landing on Mars has a vertical velocity toward the surface of Mars of 5.5m/s. At the same time, it has a horizontal velocity of 3.5m/s.

a. At what speed does the vehicle move along its descent path?
b. At what angle with the verticle is this path?

Please help me.
I don't understand how to figure this problem out.

2006-10-28 12:42:31 · 2 answers · asked by swimmertommy 1 in Science & Mathematics Physics

2 answers

a. pythagoras' theorem gives sqrt(5.5^2 + 3.5^2) = 6.52 m/s.
b. tan(3.5 / 5.5) = 0.738906894 = 42.3362465 degrees

2006-10-28 12:52:04 · answer #1 · answered by turkeyphant 3 · 0 0

Create a right-angle triangle with sides 5.5m/s long (vertical)and 3.5m/s long (horizontal), perpendicular to each other. (Connect the ends of these lines) Use trigonometry to calculate the hypotenuse and the angle of it to either the horizontal or vertical.

2006-10-28 19:58:43 · answer #2 · answered by Anonymous · 0 1

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