A descent vehicle landing on Mars has a vertical velocity toward the surface of Mars of 5.5m/s. At the same time, it has a horizontal velocity of 3.5m/s.
Please help me.
I don't understand how to figure this problem out.
2006-10-28 12:33:38 · 3 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics
pythagoras' theorem gives sqrt(5.5^2 + 3.5^2) = 6.52 m/s.
2006-10-28 12:36:12 · answer #1 · answered by turkeyphant 3 · 0⤊ 0⤋
pythagorian theorom. (5.5m/s)^2 + (3.5m/s)^2= x^2
you basically have 2 vectors 5.5i 3.5j and you have to get the new vector. if the angle is 90 degrees as this one is you can just use pythagorian if it wasnt 90 you would have to use trig
this is 6.51 m/s
2006-10-28 19:40:37 · answer #2 · answered by RichUnclePennybags 4 · 0⤊ 1⤋
www.bbc.co.uk/bitesize
2006-10-28 19:35:07 · answer #3 · answered by gareth khaajgie 1 · 0⤊ 1⤋