How would I find the net force acting on this ring? Click to see.?

Question

Here is the figure of the ring and the forces acting on it.
How would you find the net force acting on the ring?
I need help.

Picture url:
http://img415.imageshack.us/my.php?image=scanud4.jpg

Answer 1

The other guy got the forces confused. The true answer is:

sqrt(((64 + (128 * cos(30)) - 128)^2) + ((128 * sin(30))^2)) N = 133.987851 N

Answer 2

The horizontal forces resolve to -64N + 128cos30 = +46.851
The vertical force is 128sin30 = +64

So, the net force is root(46.851^2 + 64^2) = 79.316 N
at an angle above horizontal of
arctan (46.851/64) = 36.2 deg