Algebra math question!?

Question

The combined ages of Mary and Ann is 44. Mary is now twice as old as Ann was when Mary was half as old as Ann will be when Ann is three times as old as Mary was when Mary was three times as old as Ann. How old are Mary and Ann now?

Answer 1

my guess is that mary is 27.5 and Ann is 16.5

that seems to work with the way I read the problem but there are an awful lot of opportunities to misread it since there are so many steps

if mary is 16.5 when ann is 5.5, the mary is 3 times ann's age.

if ann will be 3 times as old as mary was at the above time, then ann will be 16.5*3= 49.5.

if mary was half of ann's age at the last mark, then mary was 49.5/2 = 24.75

now if mary is 24.75, that is 8.25 years later than when she was 16.5. So ann has also aged 8.25 to 13.75.

Now mary is twice as old as ann was at the last mark, so mary is 2*13.75 = 27.5

so mary has aged 11 years from 16.5 so ann has aged 11 years from 5.5. so ann is 11+5.5= 16.5

27.5+16.5= 44

Answer 2

Is this a serious question or are you insane?

M+A=44
M=2A( 1/2(3A(3M(3A))))
M=2A(13.5(A^2*M))
M=27A^3M
1=27A^3
1/27=A^3
1/3=A
M=43+2/3

That was crazy.

Check
43.66=2*.33( 1/2(3*.33(3*43.66(3*.33))))
43.66=2*.33(1/2(3*.33(131)
43.66=2*.33(1/2(3*43.66)
43.66=2*.33(1/2(131)
43.66=2*.33(65.5)
43.66=2*21.83333
43.66=43.66

Answer 3

copy it down exactly cuz ur info is to unclear

Answer 4

i'm so confused! its like a tongue-twister...i'm sorry, i tried but i don't know :S