Which of the following designations, polar or nonpolar, are correct for the given compounds below ?
a) HF : polar
b) NH3 : nonplar
c) CH3CH2CH2OH : nonpolar
d) I3- : polar
2006-10-28 11:42:03 · 6 answers · asked by MARK 2 in Science & Mathematics ➔ Chemistry
(a) It is polar because F is more electronegative than H.
(b) It is polar because N is more electronegative than H and it has a pyramidal shape.
(c). Also polar. Oxygen atom is more electronegative than carbon or hydrogen atom.
(d) Non-polar
2006-10-28 12:12:42 · answer #1 · answered by Dimos F 4 · 0⤊ 0⤋
Look at the elements in a molecule. If they differ in their electronegativities (ability to attract electrons), then the molecule is likely to be polar. Groups 5, 6, 7 generally have highly electronegative elements.
HF is polar because F (group 7) is the most electronegative element while H (group 1) has a low electronegativity
You can use the same reasoning to solve b & d.
As for c, most organic compounds are usually non-polar but alcohols are polar. In this case, I would guess that CH3CH2CH2OH has little, if any, polarity.
Hope this helps you understand the concepts. Good luck!
2006-10-28 11:58:00 · answer #2 · answered by Mary 3 · 1⤊ 0⤋
Mary is correct but other than electronegativity, the shape of the molecule it self is also affects polarity of the molecule. For example NH3 molecule is a pyramid with N on the apex of the pyramid. One pair of electrons of the N are located in one side of the nitrogen and the 3 hydrogens are on the other side:
. .
N
/ l \
H H H
As you can see the 2 electrons on the nitrogen push the hydrogens to one side. At the same time N has a higher electornegativity then H , therefore one side of the molecule, the N side, is more negative than the other side , H side. So the molecule is polar.
2006-10-28 12:16:38 · answer #3 · answered by smarties 6 · 0⤊ 0⤋
CCl 4 -Carbom Tetrachloride molecules lack molacular dipoles and thus are non polar. Water molecules are polar and CCl4 is, therefore, immiscible in water. The non polar CCl4 will however mix with Iodine because of the likeness betwqeen their intermolecular forces. As far as solubility it's a case of: "Likes like Like" Gasoline and oil, water and alcohol, salt and water, lead and copper, etc..
2016-03-28 10:21:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋
as i know, a and b are correct but not sure about d.
and because CH3CH2CH2OH has an OH molecule and is not entirely made of CH molecules, it could be polar. but i'm not sure.
2006-10-28 11:46:46 · answer #5 · answered by ___ 4 · 0⤊ 0⤋
DONT, HAVE MUCH OF AN ANSWER, BUT ARE U a UTM, student, u know thats whats to to be on the test on monday
2006-10-28 12:37:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋