A person desire to reach a point that is 3.49km from her present location&in a direction that is 35 degree north of east.However,she must travel along streets that go either north-south or east-west.WHAT IS THE MINIMUM DISTANCE SHE COULD TRAVEL TO REACH HER DESTINATION?
2006-10-28 09:02:13 · 6 answers · asked by Live & Let Live! 1 in Science & Mathematics ➔ Mathematics
3.49[(sin(35*)+cos(35*)]km
2006-10-28 09:12:11 · answer #1 · answered by raj 7 · 0⤊ 0⤋
U can form a right angled triangle
u know the two angles now and the hypotenuse
now apply sin formula
sin90/3.49=sin35/x=sin55/y
by applying this formula u will get value of x and y as
x=2.00178
y=2.8588
total distance travelled by the person =4.86km
2006-10-28 09:11:11 · answer #2 · answered by Anonymous · 0⤊ 0⤋
draw the diagram of the person's destination,
x= 3.9*cos35
y= 3.9*sin 35
x= 3.195km
y=2.2369km
that is the shortest distant to get to her final destination.
3.195km on the east- west street, and 2.2369km on hte north- south street.
2006-10-28 09:13:35 · answer #3 · answered by toye7690 1 · 0⤊ 0⤋
list the any 10 place computer are used
2015-05-28 14:27:35 · answer #4 · answered by Shiva 1 · 0⤊ 0⤋
will she get a bus .plane,bike,taxi,or she will walk?
2006-10-28 15:07:38 · answer #5 · answered by Anonymous · 0⤊ 0⤋
4.86 KM.
2006-10-28 09:32:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋