Ok can anyone help me solve this molarity problem? I am normally pretty good at these but this one just stumped me. Ok you have 25.0 ml of NaOH and it is combined with 5.72 grams of BaSO4. what is the molarity of the NaOH?
2006-10-28 08:34:56 · 3 answers · asked by dairydahm 2 in Education & Reference ➔ Homework Help
find moles of BaSo4, then assuming that there are no leftovers int he reaction, there will be the same amount of oles of naoh
then put ml of naoh to liters, then divide number of moles of naoh by the liters
2006-10-28 08:50:30 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I think you got a trick question here.
BaSO4 is insoluble and Ba(OH)2 issoluble. So adding BaSO4 to a volume of NaOH solution will not change its molarity. As you did not specify the molarity, the answer is
No change in molarity.
2006-10-28 18:02:14 · answer #2 · answered by A S 4 · 0⤊ 0⤋
2NaOH+BaSO4=Ba(OH)2+Na2SO4
atomicweight of Ba=137.34 sulphur=32 and Oxygen=16
so molecular weight of BaSO4=185
185 grams of BaSO4 will combine with
2*(23+16+1)grams of NaOH=80grams
5.72 grams will combine with 5.72*80/(185)
=2.47 grams of NaOH
2.47 grams in 25 ml
now you say you are good at it.so you
can calculate the molarity
2006-10-28 15:56:24 · answer #3 · answered by raj 7 · 1⤊ 0⤋