test your math skills yet again?

Question

1: In a square pyramid the edge of the base is 24 inches, the slant height is 20 inches, and the altitude is 16 inches. Find the lateral area (the surface area of the triangular sides only).
850 sq. in
900 sq. in
960 sq. in
990 sq. in


2: In a square pyramid the edge of the base is 24 inches, the slant height is 20 inches, and the altitude is 16 inches. Find the total surface area (the surface area of all sides of the pyramid).
960 sq. in
1115 sq. in
1230 sq. in
1536 sq. in


3: In a square pyramid the edge of the base is 24 inches, the slant height is 20 inches, and the altitude is 16 inches. Find the volume.
2785 cu. in.
2568 cu. in.
3140 cu. in.
3072 cu. in


4: An open grain hopper is in the form of an upside-down square pyramid (with the base on top and vertex below). The base is 10 square feet, the slant height is 13 feet, and the altitude 12 feet. How many bushels of wheat can it hold level full if 1 bushel occupies 1 cubic foot?
Tip: Find the volume. Since 1 bushel = 1 cubic foot, then the volume is the same as the number of bushels.
43
40
20
36


5: A marble monument is made in the form of a square pyramid. The edge of the base measures 2.35 feet and the altitude is 9.65 feet. Find the weight of the monument if the marble weighs 250 pounds per cubic foot.
Tip: Find the volume. Multiply the volume by 250 to find the total weight.

4441 lbs.
3500 lbs.
3758 lbs.
4057 lbs.

Answer 1

1. 1/2 base x height x 4
3. 1/3 altitude x area of the base
4. 1/3 altitude x area of the base
5. 1/3 altitude x area of the base x density
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Answer 2

So what's the problem? Are you not able to crank your calculator?

1. 1/2 base times height times 4
2. add the area of the bottom
3. 1/3 altitude times base area
4. 1/3 altitude times base area
5. 1/3 altitude times base area times density