maths questions???

Question

Can you help me with these questions:

(a) p(-1,2) and r(3,4) are two points.
(i) find m, the midpoint of [pr]
(ii) find the slope of pr.
(iii) find the equation of the line L, the perpendicular bisector of [pr].
(iv) the equation of the line K is x-2y=0.
Find n, the point of intersection of Land K.
(b)Prove that the opposite sides and opposite angles of a parallelogram are respectively equal in measure.

thanks

Answer 1

ok
the midpoint is (1,3)
the slope is 1/2
line L is y=-2x+5
and the intersection is (2,1)
i don't know the answer to the last problem sorry.

Answer 2

midpoint=(3--1)/2,(4-2))/2= (2,1)

slope= (4-2)/(3--1)= 2/4= 1/2

L= y= -1/2(x-2) has a slope negative of pr through the point (1,2)

inersection of L and K ....solve the at da same time...that will be youe x and y

Answer 3

Yes, I can help you out.
Maths in my country(India) is different from that of your country therefore I am able to do (a)(i) and (b) only.


(a)(i)
Let the mid point of pr be M(x,y)
Then,
M(x,y) = [(x1+x2)/2 , (y1+y2)/2]
= [(-1+3)/2 , (2+4)/2]
= [ 2/2 , 6/2 ]
= [ 1 , 3]

Ans. The mid point of pr is M (1,3)

(b)

Given: ABCD is a parellelogram
Construction: Join BD
To proove: AB = CD , AD = BC
angle DAB = angle BCD , angle ABC = angle CDA

Proof : -

In traingle DAB and traingle BCD

BD = BD (common side)
angle ABD = angle BDC (AB II CD)
angle ADB = angle DBC (AD II BC)

Thus, traingle DAB is congurent to traingle BCD (A.A.S)

Hence prooved that :

AB = CD
angle DAB = angle BCD (CPCT)

Similarly , you can proove the remaining sides and angles.

=> I was not able to provide figure but if you are good in Maths you will be able to draw by the instructions provided.

If you didnot follow any step then make me aware on my email :
[e-mail]

Answer 4

First you must draw a graph in a cartesion plane and find answers

Answer 5

This is graphs >.<...
Not sure whether this is the right place to ask...

Answer 6

but wat will happen if you accidentally pushed away the paralelogram.. then its all ruined..