I NEED HELP ASAP... Please HELP!!! Can't seem to solve!!!?

Question

( ^ represents to the power of )

1. (8x^3 y^2 z^2) * 3x^2
--------------------------
y^3 z^4

2. 200^0
--------------------
400


3. (u^8 z^7)
--------------------------
z^-3 u^-2

4. - (3a^6 b^4) ^3


5. ( 6a^2 ) ^3
( --------- ) Lines around equation represent brackets
( 7b^3 )


6. 9x - 21
--------------------------
15x - 35

7. 6 - 2x
--------------------------
4x - 12

Answer 1

I pity the fool that posts their homework

Answer 2

These are simple problems of exponentials involving multiplication and division of polynomials and exponentials.
a. Divide the final value by the first value to get the answers.
b. convert all exponentials to numerator

1. (8x^3 y^2 z^2) * 3x^2
= 24 x^5 y^2 z^2

now, y^3 z^4/(24 x^5 y^2 z^2)
= 1/(24x^5 y^-1 z^-2)
= 1/24(x^-5 y z^2) Ans

2. 200^0
= 1
now, 400/1 =400Ans

3. z^-3 u^-2/(u^8 z^7)
= z^-3 u^-10 z^-7 Ans

4. - (3a^6 b^4) ^3
= - 3^3 a^6*3 b^4*3
= - 27 a^18 b^12 Ans
(*= multiplication)

5. ( 6a^2 ) ^3 = 6^3 a^2*3 = 216 a^6
( 7b^3 )/216 a^6
= 7/216 (b^3 a^-6) Ans

6. (9x-21)= 3(3x-7)
(15x-35) = 5(3x-7)

(15x-35)/(9x-21)= {5(3x-7)}/{3(3x-7)}
= 5/3 Ans


7. (6-2x) = 2(3- x)

(4x-12) = 4(x- 3) = -4( 3-x)

(4x-12)/(6-2x) = {-4( 3-x)}/{2(3- x)}

= -2 Ans

Answer 3

ok... y=ay^2 + by technique of + c so if 4y^2 + 5 = 12y then 4y^2 - 12y + 5 = 0 subsequently a=4, b= -12 and c = 5 and considering that y= ( - b +/- ( b^2 - 4ac )^0.5 ) / 2a ( ^0.5 skill sq. root whats contained in the brackets. ) then y = ( 12 +/- ( -12^2 - 4*4*5 )^0.5 ) / 2*4 y = ( 12 +/- ( 100 and 44 - 80 )^0.5 ) / 8 y = ( 12 +/- 8 ) / 8 2 solutions are a million) y = ( 12 + 8 ) / 8 = 2.5 2) y = ( 12 - 8 ) / 8 = 0.5 Heh... amended. ignored a minus signal there.

Answer 4

I'm defintly not doing your homework. I do my own homework. Why don't you listen in school, dumbo. It's not like I'm going to spend my day doing homework on a weekend. Why don't you get a caculator. No offense but I learned this stuff when I was in 5th grade!

Answer 5

1. 8(x^3)(y^2)(z^2) * 3(x^2)
-------------------------------
(y^3)(z^4)
=(8*3)[x^(3+2)][y^(2-3)][z^(2-4)]
=24(x^5)[y^(-1)][z^(-2)]

24(x^5)
= -----------
y(z^2)

Answer 6

The time spent typing should have been spent solving.

Answer 7

This is not the forum to solve your homework.

Answer 8

Its pretty simple, PAY ATTENTION IN CLASS FOO'

Answer 9

i'm sorry, i tried but i guess i'm just as bad at maths as you are

Answer 10

haha do your own damn homework