2006-10-27 22:23:40 · 6 answers · asked by varungk92 1 in Science & Mathematics ➔ Mathematics
log(0.06)=log(2)+log(3)-log(100)
where log(100)=2
2006-10-27 22:29:24 · answer #1 · answered by meg 7 · 1⤊ 0⤋
log 6 = log(2*3)
= log 2 + log 3
= 0.3010 + 0.4771
= 0.7781
log 0.06 = 2¯.7781 (bar2.7781)
OR
= -2 +0.7781
= -1.2219
2006-10-28 05:33:31 · answer #2 · answered by grandpa 4 · 0⤊ 0⤋
log 0.06
= log (0.01 * 6)
= log 0.01 + log 6
= -2 + log 6
= -2 + log (2 * 3)
= -2 + log 2 + log 3
= -2 + 0.3010 + 0.4771
= -2 + 0.7781
= -1.2219
2006-10-28 05:31:33 · answer #3 · answered by Louise 5 · 0⤊ 0⤋
log (3*2/100)
= log 3 + log 2 - log 100
and these logs are base 10, so
log 100 = 2
2006-10-28 05:29:49 · answer #4 · answered by Hy 7 · 0⤊ 0⤋
log 0.06=log(6/100)
=log6-log100 {log(a/b)=loga-logb}
=log(2*3)-log(10^2)
=log2+log3-2log10 {log(ab)=loga+logb}
=0.3010+0.4771-2*1
=-1.2219
2006-10-28 09:04:16 · answer #5 · answered by chill 2 · 0⤊ 0⤋
Dude, you shouldn't be having other people doing your homewwork problems. If your teacher searches Yahoo Answers, you're toast!
2006-10-28 05:37:48 · answer #6 · answered by polyglot_1234 3 · 0⤊ 0⤋