If four dice are rolled, what is the probability that each of the four numbers that appear will be different?

Answer 1

(6*5*4*3)/(6*6*6*6)

=360/1296

=.2778*100%

=27.78%

Answer 2

Each die will be expressed by a probability. The first die isn't really crucial, since it has a six in six chance of being an allowed number. (6/6) But we may as well include it, to show all our work...
Each one after that will be decreased by one in the numerator:
5/6 (Five in six chance of being different from the first die)
4/6 (Four in six chance of being different from the first two)
3/6 (Three in six chance of being different from the other three.)
Each probability, expressed as a fraction, is all multiplied ... to get 360/1296
which can be simplified = 180/648 = 90/324 = 45/162 = 15/54
until we get = 5/18 "Five in eighteen chance."
Which is the simplest fraction.
Or 0.277_ (repeating non-terminating decimal) if you don't like fractions.

Answer 3

in case you want to locate the chance of rolling a best precisely 4 situations on 15 throws, no more effective, no a lot less, then you definitely take the chance of the shape occurring 4 situations prolonged by technique of the chance of the shape not likely on the ultimate situations. Order doesn't count number. you'll have: (4/10)^4 X (6/10)^11 = 0.0093%

Answer 4

6/6 * 5/6 * 4/6 * 3/6 = 60/216 = 30/108 = 15/54 ? I think. I don't have a calculator, but the method is sound.

Answer 5

6/6 X 5/6 X4/6 X3/6=5/18

Answer 6

4*6sides =24
The probability that each of the 4 numbers that appear will be different= 1/6 further divided by 4.
(PROBABILITY of correctness of this answer is uncertain!)

Answer 7

n(s)=6{power4}
n(s)=1296 A=1290{since the same numbers can be possible only for 6 values}
p(A)=n(a)/n(s)=1290/1296
=645/648

Answer 8

6*5*4*3/(6*6*6*6)

Answer 9

288/1296

Answer 10

(1/6)(1/5)(1/4)(1/3)=1/360

because each time one less number is applicable