2006-10-27 20:47:10 · 20 answers · asked by safa o 1 in Science & Mathematics ➔ Mathematics
Think about it...
Anything over 0 = 0
Therefore x= -2
2006-10-27 21:38:57 · answer #1 · answered by Anonymous · 0⤊ 2⤋
X=0
2006-10-27 20:51:02 · answer #2 · answered by ladynamedjane 5 · 0⤊ 1⤋
(x+2) = 1 / 0 = ∞
or, x = ∞ -2 = ∞
or, x = ∞
2006-10-27 20:52:40 · answer #3 · answered by The Potter Boy 3 · 0⤊ 1⤋
1/(x+2) = 0
(x+2)=(0*1=0)
(x)=(0-2=-2)
x=(-2)
2006-10-27 20:58:01 · answer #4 · answered by OoO 4 · 0⤊ 1⤋
toesnt have a solution.
1/(x+2) = 0
multiply both sides with (x+2) , for x !=-2 this is allowed.
then 1 = 0*(x+2) or 1 = 0; no solutions for x!=-2
for x = -2
you have 1/(-2+ 2) = 0 , here the lefthandside is undifiend ( 1/0 ) thus no x=-2 isnt a solution either,
2006-10-27 21:19:34 · answer #5 · answered by gjmb1960 7 · 1⤊ 1⤋
I find it shocking how many people gave a bad answer to this one. You should not be using the Math section of Yahoo Answers if you don't know that 1/0 is undefined, and is definitely not 0.
No real number is a solution to this equation. However it is true that the value of 1/(x+2) can be made arbitrarily close to 0 if x is sufficiently large in absolute value.
2006-10-28 01:58:34 · answer #6 · answered by ted 3 · 0⤊ 1⤋
There is an error in the equation or it is incomplete
multiplying both sides by (x+2)
we get 1 =0 which is impossible.
2006-10-27 21:21:27 · answer #7 · answered by Venkatesh V S 5 · 1⤊ 1⤋
The answer is undefined because there is no value of x that would make this equation equal to zero. You can see this if you graph it. As you approach x = -2, the graph goes towards positive infinity on the right and goes towards negative infinity on the left. 1/0 is not a number. It is undefined or infinity.
2006-10-27 20:55:10 · answer #8 · answered by Anonymous · 1⤊ 1⤋
x= -2
1/(-2+2) = 0
1/0=0
2006-10-27 20:51:51 · answer #9 · answered by Wiseguy 3 · 0⤊ 1⤋
1/(x+2-2)=0-2
1/x=-2
(1)1x=-2(1)
x=-2
Check
1/(-2+2)
=1/0
=0
2006-10-27 21:00:02 · answer #10 · answered by Anonymous · 0⤊ 1⤋