Suppose that u have two lamps M and N that are not identical. You observe that M is brighter than N in a series circuit. What does theory tell u about the following
a) The VOLTAGE across M compared the voltage across N
b) The RESISTANCE of M and N
c) The current in M compared with the current in N in the parallel circuit
d) The BRIGHTNESS of M compared with N in the parallel circuit.
2006-10-27 20:06:38 · 4 answers · asked by Tavis T 1 in Science & Mathematics ➔ Physics
The bulb glows brighter means the voltage across that bulb is high.As both the bulb are connected in series the current in both the bulb is same. M glows brighter means the voltage across it is higher and its resistance of the filament is high then N.
2006-10-27 20:15:14 · answer #1 · answered by Manoj 1 · 0⤊ 0⤋
The current in the series circuit is the same in both lamps. The brightness of the lamps will depend on the power dissipated by the lamp. The power is I^2*R; the resistance of M must be higher than N. If the current is the same and the resistance is higher, the voltage across M must be higher than the voltage across N. In a parallel clrcuit, the lower-resitance lamp will draw more current, so then N will be brighter than M in a parallel circuit.
2006-10-28 03:18:14 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
the first one. (a)
2006-10-28 03:19:39 · answer #3 · answered by Anonymous · 0⤊ 0⤋
b) The RESISTANCE of M is higher then N
2006-10-28 03:43:23 · answer #4 · answered by vijay4118 2 · 0⤊ 0⤋