Frenz, help me to solve this Physics quest!!?

Question

Hi....I have many problems about my physics homework. may anyone help me...plesszz...

An apple falls from a tree of height 2.3m. What is the velocity
of the apple right before it lands on the ground?

I already know its answer, but how to get its answer??!!help me..

thanks for ur responses! But I reallly don't understand what u mean by 'd'? Is it the velocity? b'coz in my syllabus, 'v is for velocity...

Answer 1

Hint: Use the first eqn of motion

final velocity = initial velocity + at

You will see that you need to solve for the time before you can find the final velocity (initial velocity is zero because the apple was at rest when it was hanging from the tree, a = 9.8 m/s^2)

So to find time, use the 2nd eqn of motion:

d = initial vel x t + 1/2a(t^2)
d= 1/2g(t^2) because initial vel is zero

Solve for time, and plug it into the first eqn

good luck!

Answer 2

Vf^2 - Vi^2 = 2as

Vf = final velocity
Vi = initial velocity = 0 in this case
s = distance = 2.3m in this case
a = acceleration = g = 9.8 m/s^2 in this case

Vf = sqrt(2 * 9.8 m/s^2 * 2.3 m) = 6.7 m/s

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FYI, in the first answer given, d is distance
use the method in the first answer to derive the equation I started with.

Answer 3

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Answer 4

Please apply the formula v^2=u^2+2as,where v=final velocity,u=initial velocity,a=accelaration due to gravity and s=distance travelled by the object.Putting u=0 (as the apple was at rest initially), a=9.8 m /sec^2and s=2.3 m(the height of the tree),we get v^2= 0+2*9.8*2.3 => v^2=45.08 Therefore.v=radical 45.08=6.7m/sec

Answer 5

Vf^2=Vi^2+2ad
Vf is the final velocity
Vi is the initial velocity
a is the acceleration, gravity is 9.8m/s^2
d is the distance

Answer 6

d in the first problem is the vertical distance (in ur case, that would be 2.3)

Answer 7

You need the time to be able to do that.