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Find the area of the rectangle
one side is square root of 3 + square root of 5
the other side is the same square root of 3 + square root of 5

2006-10-27 14:05:44 · 12 answers · asked by George F 1 in Science & Mathematics Mathematics

12 answers

15.7459666924

or rounded as 16

2006-10-27 14:18:40 · answer #1 · answered by Shaula 7 · 2 1

the area is the square root of 15

2006-10-27 16:36:50 · answer #2 · answered by peterwan1982 2 · 0 0

enable L and B be the size and breadth resply of the rectangle Now provided that, P = 2(L + B) = 30 and A = L * B = fifty 4 or L + B = 30 / 2 L = 15-B ........eqn I and L = fifty 4/B ...... eqn II hence we get fifty 4 / B = 15 - B (from eqn I and II) B^2 -15B + fifty 4 = 0 B = 6 , 9 whilst B is 6 L is 9 and whilst B is 9 L is 6 hence, the longest component of the rectangle is 9 inches.

2016-11-26 00:04:49 · answer #3 · answered by Anonymous · 0 0

Area of the rectangle = (root 3)(root5)
= root 15

2006-10-28 01:13:49 · answer #4 · answered by Akilesh - Internet Undertaker 7 · 0 0

A = (√3 + √5)^2
A = 3 + 2√15 +5
A = 8 + 2√15
A = 2(4 + √15)
A = 15.746

2006-10-27 14:20:15 · answer #5 · answered by Helmut 7 · 0 1

The answer is 8+2(sqrt 15). Think of it as squaring a two-variable equation. (x+y)^2=x^2+2xy+y^2. If x=sqrt 3 and y=sqrt 5, then x^2=3, xy=sqrt 15, and y^2=5.

2006-10-27 14:18:23 · answer #6 · answered by Ivallinen Roisto 2 · 2 2

A square, then.

(sqrt(3) +sqrt(5)) ^ 2 = 3 + 2sqrt(3)sqrt(5) + 5

= 8 + 2sqrt(15).

2006-10-27 14:34:54 · answer #7 · answered by Anonymous · 0 1

??? What planet are those answers from???


One side is sqrt(3) + sqrt(5).
Other side is sqrt(3) + sqrt(5).

Unless you mistyped the problem, this is a square.

(sqrt(3) + sqrt(5))*(sqrt(3) + sqrt(5)) = 3 + 5 + 2*sqrt(3)sqrt(5) = 8 + sqrt(15)

2006-10-27 14:21:38 · answer #8 · answered by sofarsogood 5 · 0 1

What other side? Are these sides parallel? you need to give the non parallel side otherwise. If these are not the parallel sides but are adjacent, then the area is (sqrt 3 + sqrt 5)(sqrt5 + sqrt 3)

2006-10-27 14:15:20 · answer #9 · answered by maggie_at0303 3 · 0 2

8.73333

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2006-10-27 14:19:58 · answer #10 · answered by Reston 4 · 0 3

Area = Height x Width
Height = sq.rt of 3 + sq.rt of 5
Width = sq.rt of 3 + sq.rt of 5
Area = Height x Width
Height = Width
Area = Height^2 (squared)
Area = (sq.rt3 + sq.rt5)^2, = (sq.rt 3)^2 + (sq.rt5)^2
Area = 3 + 5
Area = 8

2006-10-27 14:14:32 · answer #11 · answered by Charly Bravo 3 · 0 3

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