Question: If 3 times the supplement of an angle is subtracted from 7 times the complement of the angle, the answer is the same as that obtained from trisecting a right angle. Find the supplement of this angle.
2006-10-27 14:04:28 · 6 answers · asked by 2 days after my B day :) 2 in Science & Mathematics ➔ Mathematics
Let x be the angle
Supplement of x = 180-x
Complement of x = 90-x
Trisection of a right angle = 1/3 of right angle = 1/3rd of 90 =30
so, 7(90-x) - 3(180-x) = 30
630 -7x -540 +3x = 30
90 - 4x = 30
4x = 90 - 30 = 60
x =15
But what is needed is supplement of this angle
= 180 - 15 = 165
(This is a trick question. Normally we get numerical value for x and consider that as the answer)
2006-10-27 23:30:09 · answer #1 · answered by grandpa 4 · 0⤊ 1⤋
Let the angle be x
7(90 - x) - 3(180 - x) = 90 /3
630 - 7x - 540 + 3x = 30
90 - 4x = 30
- 4x = -60
x = 15
2006-10-27 14:18:03 · answer #2 · answered by maggie_at0303 3 · 0⤊ 0⤋
7(90-a)-3(180-a)=90/3
a=30 degrees
Supplement of a is 120 degrees, if I understand the question correctly. :)
2006-10-27 14:11:11 · answer #3 · answered by Your Best Fiend 6 · 0⤊ 0⤋
complementary=ninety levels supplementary=a hundred and eighty levels good success! and guess what. in a triangle, once you upload up each and every of the angles, they diploma a hundred and eighty levels. continuously. in case you have angles that diploma greater effective than that, a triangle will no longer be able to be formed
2016-12-16 15:34:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
This exact problem was on a test in my geometry class.
2006-10-27 14:32:49 · answer #5 · answered by Anonymous · 0⤊ 0⤋
7(.5x)-3(x)=30
3.5x-3x=30
.5x=30
x=60
supplement=60
2006-10-27 14:31:11 · answer #6 · answered by Anonymous · 0⤊ 0⤋