Why is it that?

Question

to solve the probability of dealing 2 consecutive queens in a fresh deck of cards you have to multiply 4/52 * 3/51?

Can someone please explain probability?

Answer 1

well there are four queens and 52 cards. So the first part of the equation is rather obvious. Now after you've drawn one queen there are only 3 queens and 51 cards left. In order to determine all the sequence permutations - you multiply the two fractions 4 queens/52 cards time 3 queens/51 cards. 12/2652 which reduces to 1/221. So...odd are one try in 221 that you will draw two queens in a row!

Answer 2

Because if you randomly select a card and want a queen, there are 4 queens in a deck of 52 cards, so the chance of getting the Q is 4/52.
We have already drawn one card, and there are 51 left. Three of those are queens, so the chance of getting the second queen is 3/51.
To find the probability that both things happen - that we get 2 queens, we multiply those probabilities

Answer 3

when drawing the first card there are 4 queens in the deck so you have a 4/52 chance of drawing a queen. Now multiply that probability by the chance of drawing a queen again. On the second draw there are only 3 queens left and 1 less card in the deck so the probability of drawing a queen the second time is 3/51

Therefore the probability of drawing a queen twice is:
4/52*3/51

Answer 4

Hi. Break up the problem like this. (4/52) * (3/51). There are 4 chances in 52 of getting the first queen. There are 3 chances in 51 (one card is already gone) of getting the second queen. If the question was THREE queens the next part would be to multiply (2/50). Make sense?

Answer 5

You can look at it another way, using combinations:

There are C(52,2) = 1326 ways to pick any two cards out of the 52 in the deck.

Out of all these combinations, there are C(4,2) = 6 ways to pick two queens out of the four.

Hence the probability is 6/1326, or 1 / 221.