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6 answers

12*3+1*5+16*9+14*3=227

2006-10-27 13:53:36 · answer #1 · answered by kmbell81 2 · 1 0

Replacing these elements with their molar masses and summing gives us C3H5(NO3)3 = 12*3 + 1*5 + (14 + 16*3)*3 = 227 g.

2006-10-27 13:50:50 · answer #2 · answered by DavidK93 7 · 1 0

C3H5(NO3)3
Using integer AMU's:
M = 3*12 + 5 + 3*14 + 3*3*16
M = 36 + 5 + 42 + 144
M = 180 + 47
M = 227 g

2006-10-27 13:54:05 · answer #3 · answered by Helmut 7 · 0 0

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2016-04-25 12:55:35 · answer #4 · answered by Anonymous · 0 0

(12*3) +(5*1)+(I14*3)+(16*3*3)=227

2006-10-27 13:58:04 · answer #5 · answered by ergech 2 · 0 0

4)...227g/mole

2016-05-22 02:00:40 · answer #6 · answered by Anonymous · 0 0

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