Calculus Question?

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What is the derivative of (x+y)^1/2 + (x-y)^1/2 + 3y= 16

Thanks

2006-10-27 12:25:55 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1 answers

If you want dy/dx, then you have

(1/2)(x+y)^(-1/2)(1+dy/dx) +
(1/2)(x-y)^(-1/2)(1-dy/dx) + 3dy/dx = 0.

Isolate dy/dx:

dy/dx[(1/2)(x+y)^(-1/2) - (1/2)(x-y)^(-1/2) + 3] =
-(1/2)(x+y)^(-1/2) - (1/2)(x-y)^(-1/2)

Solve for dy/dx:

dy/dx = -(1/2)[(x+y)^(-1/2) + (x-y)^(-1/2)] / [(1/2)(x+y)^(-1/2) - (1/2)(x-y)^(-1/2) + 3]

2006-10-27 12:29:45 · answer #1 · answered by James L 5 · 0⤊ 0⤋