How does the change of the position of weight on a rolling object (skateboard) affect its speed?

Answer 1

It shouldn't. It will affect your controllability by shifting the forces forward or backward and, therefore, more over your front wheels when moving forward or the back wheels when moving backward. Shifting forward should be more stable (controllable)than shifting backward. But further back is where you want to be for quick responses and changes in direction even though you run the risk of crashing from being uncontrolled.

The center of gravity (CG) forward when you are forward on the board is like having a front wheel drive car. A FWD car is more stable (controllable) than a rear wheel drive car because the CG in a FWD car is more forward than the CG on a comparable RWD car.

As another example, an arrow flys better pointy end first because it is more stable than trying to shoot it feather end first. That's because the CG is forward when shooting pointy end first and back when trying to shoot it feather first.

The speed you have is predicated on how much energy you put into the skateboard and kinetic energy (the energy of motion) is based on the force you pushed off at regardless where you were standing on the skateboard when you pushed off. The energy expended is equal to force X distance you roll.

Answer 2

There are 2 opposing forces alongside the exterior of the ramp that confirm the internet rigidity and, for that reason, the acceleration of the ball down the ramp. the 1st is the motivating rigidity w = W sin(theta), the place W = mg is the load of the ball and theta is the incline perspective of the ramp. the 2d is the retardation rigidity from friction f = kN = kW cos(theta) = kmg cos(theta); the place ok is the coefficient of rolling friction. positioned the two jointly and you have the internet rigidity: F = ma = w - f = mg(sin(theta) - ok cos(theta); so the acceleration down the ramp is: a = g(sin(theta) - ok cos(theta)). And there you're activities followers. Neither m, the mass of the ball, nor W, the load of the ball make a distinction in the value of acceleration down the ramp. Your errors are ordinary of defective experimentation. by way of fact the three balls are diverse length, they in all risk lie alongside the ramp's instruction manual rail and touch the facets of the railing in diverse spots. this potential the ok, the coefficient, of rolling friction for the three balls is in all risk diverse (i'm guessing greater desirable for the bigger balls). And as you will see that from a = g(sin(theta) - ok cos(theta)) a huge ok potential a slower acceleration and consequent velocity on the backside of the ramp. So if the bigger balls are the slower balls, it quite is in all risk the place the errors in experimentation is. to dam out that risk of diverse ok's for each ball, use in simple terms one ball, yet use a ball which you will exchange the load of by including or subtracting some mass. which will shop the size and textile of the ball the comparable for each roll down the ramp. And which could consequence in the comparable ok for each trial. warning. That one experimental ball would be hollow; so which you will fill it with some thing. yet make particular it quite is thoroughly crammed with notwithstanding you place into it. otherwise the ball won't roll easily down the ramp as its innards slosh approximately. So fill it with air (empty), sand, and water, as an occasion, to the brim. which will supply the ball easy, medium, and heavy weight/mass that may not slosh approximately. Weigh the ball each and each attempt and calculate the mass m = W/g.

Answer 3

It alters its CG (center of gravity).