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3.01 x 10^23 molecules of water.

2006-10-27 12:07:30 · 4 answers · asked by Sun 1 in Science & Mathematics Chemistry

4 answers

First find the moles of water. One mole is Na = 6.02x10^23 molecules, so:

n = N/Na = 3.01x10^23/6.02x10^23 = 0.5 mol

The relative molar mass of H2O equals Mr = 18, so:

m = n*Mr = 0.5*18 = 9 g

2006-10-27 12:15:06 · answer #1 · answered by Dimos F 4 · 0 0

6.02 x 10^23 molecules of water is 1 mole or 18 gram of water (by definition).

so 3.01 x 10^23 molecules of water is 0.5 moles or 9 gram of water.

2006-10-28 00:40:26 · answer #2 · answered by Dr. J. 6 · 0 0

multiply the number of moleucules by the amu of water, H2O

2006-10-27 19:10:24 · answer #3 · answered by camopunktru 1 · 0 0

27g

2006-10-27 19:11:09 · answer #4 · answered by Anonymous · 0 1

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