How much tension must a rope withstand if it is used to accelerate a 1900 kg car vertically upward at 0.90 m/s

Question

this is a physics question.

I NEED A NUMBER ! IM A HIGH SCHOOL STUDENT IN PHYSICS!!!

Answer 1

Firstly, I think you miscopied the unit of 0.90. It should be m/s^2, right? So the car is accelerating at 0.90m/s^2. If you use 0.90m/s you are saying that the car is traveling at a speed of 0.90m/s. The problem will then be simple: the tension in the rope will just be equal to the weight of the car or mg or 1900*9.8 = 18620N. So be careful with the unit you use.

Now let's assume you meant 0.90m/s^2.

F=Ma where F is the net force on the car which makes it accelerate at 0.90m/s^2. M is the mass of the car of 1900kg.

Substitute known values:

F=1900*0.90=1710N

That's the net force acting upward. So now the tension must be more than just the weight of 18,620N. We now have to add F. Thus the tension=18620+1710=20330N.

Remember that the net force is the unbalanced force. The weight alone will be balanced by the same amount of force, but when the body is accelerating there's an extra force which we call net force. This adds to the tension in the rope. That's why we add it to the weight of the car.

Answer 2

F=ma for force due to acceleration=1900 kg* 0.90m/s^2
F=mg for force due to gravity=1900 kg*9.8 m/s^2
In your statement, it is moved upward at constant velocity at
0.90 m/s, so the force is due to gravity only.
But you said it is used to accelerate, so the force due to acceleration should be included.
The unit of 0.90 m/s is for velocity only.
If you meant the acceleration vertically upward at 0.90m/s^2, then you have 1710 Newtons due to acceleration.
Tension=1710 Newtons+ 18620 Newtons=20330 Newtons.

Answer 3

The velocity is moot, since it's apparently a constant velocity, in which case, you need to hold up the weight of car with the rope.