2006-10-27 10:41:49 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
16 g. methane is one mole, so 2 moles of O2 are required for perfect combustion.
2006-10-27 10:45:07 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
Since the atomic mass of carbon is approximately 12 and the atomic mass of hydrogen is approximately 1, the molar mass of methane is 16 g/mole. Therefore according to this equation it will take two moles of oxygen gas to burn the methane but since it exists in nature only as O2 then it will take 4 moles of oxygen to complete the reaction.
2006-10-27 10:48:18 · answer #2 · answered by Dave S 1 · 0⤊ 0⤋
In the reaction of the burning of methane producing CO2 and H2O 1 mole of CH4 is burned. (carbon weighs12 and 4 H's at one each)(16g)
CH4 + 2O2 ---> CO2 + 2H20, first balance the equation.
It shows that for every mole of CH4 burned it takes 2 moles of O2
2 moles of O2
2006-10-27 10:50:48 · answer #3 · answered by science teacher 7 · 0⤊ 0⤋
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2016-05-15 21:47:32 · answer #4 · answered by Audrey 4 · 0⤊ 0⤋
.5 L * a million mole / 22.4L * 2/a million * 22.4L / a million Stoichiometry, I kinda did it showing extra steps than mandatory you should merely multiply .5L by way of the molar ratio because of the fact that's a million:2 ratio
2016-12-08 22:42:51 · answer #5 · answered by Anonymous · 0⤊ 0⤋