ways can these boys & girls be arranged if the girls & boys can appear in any order
2006-10-27 10:06:13 · 7 answers · asked by gt 1 in Science & Mathematics ➔ Mathematics
Girls first:
1st girl can be picked 4 ways, 2nd giirl 3 ways 3rd girl 2 ways and then there is only 1 girl left for the last position
So number of ways girils can be ordered = 4 x 3 x 2 x 1
Similarly number of ways the boys can be ordered = 3 x 2 x 1
Number of ways they can all be ordered = 4 x 3 x 2 x 1 x 3 x 2 x 1
= 144
2006-10-27 10:10:39 · answer #1 · answered by Wal C 6 · 1⤊ 0⤋
3
2006-10-27 17:10:58 · answer #2 · answered by Anonymous · 0⤊ 1⤋
144
4 boys can be ararnged in any way in factorial 4 ways = 4*3*2*1 =24
3 girls can be ararnged in 3*2*1 = 6 ways
both of them to simultaneously occur it is 24*6 = 144
2006-10-27 17:15:12 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Boys. Number of permutations of 4 things taken 4 at a time = 24
Girls. Same = 24
Total number of ways = 24 x 24 = 576
2006-10-27 17:23:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Seat the girls and stand the guys behind them standing between and a little behind each seat.
2006-10-27 17:10:18 · answer #5 · answered by Bekka 3 · 0⤊ 1⤋
144 different arrangements
2006-10-27 17:36:36 · answer #6 · answered by Kathy 2 · 0⤊ 0⤋
difficult
2006-10-27 17:17:36 · answer #7 · answered by Restricted 4 · 0⤊ 0⤋