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the eiffel tower is 497 ft taller th an the washington monument. if each of the monuments were 58ft shorter, the eiffel tower would be twice as tall as the washington monument. how tall is each

2006-10-27 09:58:25 · 10 answers · asked by lumi 4 in Education & Reference Homework Help

10 answers

Okay, that's your assignment...what specific question do you have about it? Remember, a word problem is all about identifying what is known and using variables to indicate what is unknown, and then simply doing the math. What are the facts?

Let E = eiffel tower height
Let W = wash mon height

E = W + 497

2(E - 58) = W - 58 (if both were 58 feet shorter, then the eiffel tower would equal twice that of the washington monument)

Now, substitute the W equation for E and solve for W, then you can find E.

Remember, use correct order of operations, and whatever you do to one side of the equation, you must do to the other.

To everyone else -- this is called homework HELP... as in HELP someone, not "give the person the answer"

2006-10-27 10:04:25 · answer #1 · answered by Anonymous · 2 1

The first thing we need to do is to define a variable.

Height of the Washington Monument = x

Since the Eiffel tower is 497 feet higher than the Washington Monument (or x),

Height of Eiffel tower = x + 497.

If they were each 58 feet shorter means let's subtract 58 from both monuments. Now we have

Washington Monument = x - 58
Eiffel tower = x + 497 - 58, which reduces to x + 439.

At this point the Eiffel tower would be twice as tall as the Washingto Monument, or Eiffel tower = Washington Monument times 2, or

x + 439 = 2(x - 58)

x + 439 = 2x - 116 -- using the distributive property

x + 439 = 2x - 116 -- now we need to isolate x (get x by itself)

x + 555 = 2x -- added 116 to both sides

555 = x -- subtract x from both sides.

the washington monument is x, whic is 555 feet.

the eiffel tower is x + 497, which is 1052 feet.

Now we need to check. We plug 555 feet into our equation and see if it works.


x + 439 = 2(x - 58)

555 + 439 = 2(555 - 58)

994 = 994 and it checks.

A quic Wikipedia search says the Washington Monument is actually 555 ft and 1/8 of an inch. So if your math teacher has been telling you math needs to be precise or close only counts in hand grenades and horseshoes, bring this up with him or her. After all 1/8 of inch can be a big deal.

Hope this helps and you could always draw a picture to help you visualize what the question is asking.

2006-10-27 17:18:22 · answer #2 · answered by jeffmortelette 1 · 0 1

let the height of the washington monument be x ft.Therefore the height of eiffel tower is x+497ft.. If each of the monuments be 58 ft.shorter,their height would have been x-58 and x+497-58 orx+439 ft. now according to the problem x+439=2(x-58) =>x+439=2x-116 => x-2x=-116-439 => -x=- 555 =>x=555 ft.Therefore ,the height of the washington tower is 555 ft and that of the eiffel tower is 555+497 or 1052 ft.

2006-10-27 21:28:38 · answer #3 · answered by alpha 7 · 0 1

Simple...I am going to explain the answer , so you know how to go about it next time

Let height of washington monument = x
Therefore height of Eiffel Tower = x + 497

Now we form an equation using the information above


(x + 497 - 58) = 2(x - 58)

x + 439 = 2x - 116
439 + 116 = 2x - x
555 = x

Therefore washington monument = 555

Eiffel tower = 555 + 497 = 1052

2006-10-27 17:10:59 · answer #4 · answered by tonio 1 · 0 1

The Eiffel Tower would be 774.5 ft, the Washington Monument would be 277.5.

E= W+497 497-58= 439

439= (w-58)2, so 439= 2W-116, which figures to 555= 2W, so
W= 2775

w+497= 774.5=E

2006-10-27 17:10:49 · answer #5 · answered by Kitten_pmr 2 · 0 1

Let height of washignton monumnet be x
Thus height of eiffel tower will be x+497

Thus
=2(x-58) = (x+497-58)
= 2x-116 = x+439
= 2x-x = 439+116
= x = 555

Washignton monument is 555 ft tall
Eiffel tower is (555+497) = 1052 ft tall

2006-10-27 17:29:18 · answer #6 · answered by Abhay L 1 · 0 1

Let x be the height of the Eiffel tower, y be the height of the Washington monument.

Then x = y + 497, and x - 58 = 2(y - 58).

Substitute y+497 for x in the 2nd equation, and you have

y+497-58 = 2y-116
or
497-58+116 = y
so y = 555, and x = 1052.

2006-10-27 17:02:34 · answer #7 · answered by James L 5 · 2 1

let x=height of Eiffel tower
let y=height of Washington monument

x-497=y

2(y-58)=x-58 (expand this equation)
2y-116=x-58
2y=x-58+116
2y=x-174 (isolate x)
2y+174=x

sub x-497 in for y in the 2nd equation.

2(x-497)+174=x (expand)
2x-994+174=x
2x-820=x (isolate x)
-820=x-2x
-820=-x (multiply by -1 to make each side positive)
820=x

now sub 820 in for y in the first equation and solve for y.
x-497=y
820-497=y
323=y

Check:

equation 1:
x-497=y
820-497=323
323=323

equation 2:
2y+174=x
2(323)+174=820
646+174=820
820=820

Concluding statement:

Therefore, the height of the Eiffel Tower is 820 ft and the height of the Washington Monument is 323 ft.

2006-10-27 17:09:43 · answer #8 · answered by Anonymous · 1 1

the washington monument is 277.5 feet, and the eiffel tower is 774.5.......i think

2006-10-27 17:03:10 · answer #9 · answered by Anonymous · 0 2

masashilynne is right, do it her way. 555 is not right

2006-10-27 17:18:36 · answer #10 · answered by Br@d 2 · 0 0

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