Solve this problem in your notebook using all four steps.
The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.
2006-10-27 06:29:50 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a+b+c+26
b=2a
c=c+6
a=4
b=8
c=14
2006-10-27 06:33:30 · answer #1 · answered by Anonymous · 5⤊ 0⤋
the frist number is 4, the second is 8 and the third is 14 4+8+14=26
2006-10-27 06:33:52 · answer #2 · answered by sttds01 1 · 1⤊ 0⤋
Let x,y,z be the numbers
x+y+z=26
y=2x
z=6+y.
Therefore
x+y+z = x+2x+6+y = x+2x+6+2x = 26, so 5x=20. Therefore x=4, y=8, and z=14.
2006-10-27 06:35:24 · answer #3 · answered by James L 5 · 1⤊ 0⤋
The problem should be set up like this:
x+2x+2x+6=26
Combine like terms:
5x+6=26
Subtract 6 on both sides:
5x=20
x=4
2(4)=8
x=8
2(4)+6=14
x=14
x=4,8, and 14
Check:
4+2(4)+2(4)+6=26
4+8+8+6=26
12+14=26
26=26
I hope this helps!
2006-10-27 08:12:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
a + b + c = 26
b = 2a
c = b + 6 or c = 2a + 6
Put it all in the first equation:
a + 2a + 2a + 6 = 26
5a = 20
a = 4
b=2a, or 8
c=b+6, or 14.
numbers are 4, 8, 14.
2006-10-27 06:34:54 · answer #5 · answered by p_rutherford2003 5 · 1⤊ 0⤋
x + 2x + (2x+6) = 26
5x + 6 = 26
5x = 20
x = 4
First number = x = 4
Second number = 2x = 8
Third number = 2x + 6 = 14
= 4, 8, 14
;-)
2006-10-27 06:33:40 · answer #6 · answered by Jen 2 · 2⤊ 0⤋
All the answers are correct so far, 4, 8, 14, it is up for you to decide which answer is best for you to use on your homework assignment!!!!!!!!!!
2006-10-27 06:38:50 · answer #7 · answered by redhotboxsoxfan 6 · 1⤊ 0⤋
your three numbers arex1,x2,x3
Given
x2= 2*x1
x3=6+x2
x3 = 6+2*x1
x1+x2+x3=26
x1+2*x1+6+2*x1=26
5*x1=20
x1=4
x2=8
x3=14
2006-10-27 06:33:39 · answer #8 · answered by Anonymous · 1⤊ 0⤋
4
8
14
2006-10-27 07:23:39 · answer #9 · answered by dtymittal 2 · 1⤊ 0⤋