The length of each of the bonds between the atoms of a molecule of nitrogen (N2) is
0.0976 nm. The mass of a nitrogen atom is 2.32 x 10^11 pg.
Determine the moment of inertia of the molecule about an axis passing through the center of mass perpendicular to the line joining the two atoms. Ans. in units of pg nm^2.
2006-10-27 06:22:33 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
STILL NEED HELP WITH THIS ONE
2006-10-30 02:27:35 · update #1
In this case, you can treat each atom as a point mass. For point masses, the moment of inertia is the summation of mr^2 for all masses. In this case, r will be half the length of the bond, or 0.0488 nm = 4.88 x 10^-11 m and m will be 2.32x10^-11 pg = 2.32 x 10^-26 kg, where I think you made a typo in the mass of the atom. You have two identical masses with the same radius, so I = mr^2 + mr^2 = 2mr^2, using m and r from above.
2006-11-02 01:07:38 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
Nitrogen (N2) can be modeled as a dumbbell molecule. Model this like a massless rod with two balls attached (the atoms) at either end. Check your mechanics text, they will likely have the special case of the moment of intertia of a dumbbell.
2006-10-27 13:25:35 · answer #2 · answered by msi_cord 7 · 0⤊ 0⤋