Calling all mathmaticians!!!?

Question

If the 2nd year of a degree is worth 40% and the 3rd yr is worth 60% of the overall mark, if students in their 2nd year got 50% or 45% what would they need to get in their 3rd year to get an overall average of 60%? How would you work it out?

Answer 1

Whatever percentage the student got in the 2ND year, multiply it by 40 and divide it by 100.

This gives the absolute number of points he got towards his degree.

If he got 50% in the 2nd year, he got 2000/100 points

50% ->20 points

similarly,

45% -> 18 points.

These points are points out of 100 (in other words percentages of the final degree mark).

To get an overall average of 60% in the final mark, he needs to score an extra 40 (or 42) points in his 3rd year.

This means that 60% of his 3rd year mark has to be greater than 40 (or 42).

The mark, 60% of which is 40, is 40 x 100/60

=67 rounded to nearest whole number.

the mark, 60% of which is 42, is 42 x 100/60

=70.

If he got 50% in the 2nd year, he needs to get 67% in the 3rd year, for the weighted average to be 60%

If he got 45% in the 2nd year, he needs to get 70% in the 3rd year, for the weighted average to be 60%

Answer 2

the 3rd year is weighted 60/40 towards the overall
mark

let a= overall mark
b=second year mark
c=third year mark

therefore, a= 0.4 b+0.6c

>>>>> c=(a-0.4b)/0.6=(10a-4b)/6

when second year mark was 50% and the
overall mark required was 60%,the 3rd year mark
c required= (10*60-4*50)/6 = 66 2/3%

when second year mark was 45% and the
overall mark required was 60%,the 3rd year mark
c required= (10*60-4*45)/6 = 70%

i hope that this helps

Answer 3

If you got 45% in your 2nd year you'd need to get 70% in your 3rd year.
If you got 50% in your 2nd year, you'd need to get 66.67% (basically 67%) in your 3rd year.

If your interested (for the 45% in 2nd year scenario):
Work out 1st year mark as a percentage of the whole
40x0.45=18%
Overall you need 60% therefore you need to make up 60-18% = 42%
42% is only over the remaining 60% therefore
(42/60)x100=70%

Answer 4

Let x be the 3rd year mark, y be the second year.

Then you want 60 = 0.4y + 0.6x, so

x = (60 - 0.4y) / 0.6 = 100 - 2y/3.

If y=45, then x=70. If y=50, then x=66.66.

Answer 5

answer is :-
66.6666% for 50% in 2nd yr
70% for 45% in 2nd yr
The workings for 50%: -

40x + 60y = 100p
If x = 60 and p=60 ( percent )
then (40 x 50 ) + 60y = 100 x 60
2000 + 60y = 6000
60y = 6000 - 2000
60y = 4000
y= 4000 / 60
y= 66.666666

and for 45% :-

(40 x 45 ) + 60y = 100 x 60
1800 +60y =6000
60y = 6000 - 1800
60y = 4200
y= 4200 / 60
y= 70

tah-dah!!

Answer 6

you decide on the stairs to distribute (a-b) to (a^2 + ab + b^2)? through fact I recognize this (a-b) (a^2 + ab + b^2) through fact the version of cubes while factored, i visit repeat from my math e book the way the formula is derived. (a-b)(a^2 +ab +b^2) =a(a^2 + ab+b^2)- b(a^2 + ab+b^2) They broke up the (a-b) and disbursed it. = a^3-a^2b + ab^2 - a^2b - ab^2 - b^3 They did the allotting and as quickly as they integrate like words they're left with (a^3 - b^3).