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Which set of ordered pairs is a function?

(2,3),(-4,5),(2,7),(7,-2)

(2,3),(-4,5),(-2,7),(-4,-2)

(2,3),(-4,5),(-2,7),(7,7)

(2,3),(-4,5),(2,-7),(7,-2)

2006-10-27 05:32:52 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

The third one.

The rule is for each input (or x value) there is a unique output (or y value)

2006-10-27 05:35:13 · answer #1 · answered by Will 4 · 1 0

Functions have to have unique y values. Thus any set that has two different y values for the same x cannot be a function.

This eliminates
1) dups at x=2
2) dups at x=-4
4) dups at x=2

so, only set 3 has unique x,y pairs..

2006-10-27 12:44:27 · answer #2 · answered by modulo_function 7 · 0 0

A function MUST map each domain value into a unique range value, i.e., you CANNOT have two different function values for the same input value.

Only ONE of the choices meets that criteria.

2006-10-27 12:36:25 · answer #3 · answered by arbiter007 6 · 0 1

If by "function" you mean that each "x" has a unique "y", the answer is fairly obvious... look for the set that has all different "x" values.

2006-10-27 12:36:43 · answer #4 · answered by Anonymous · 0 1

(2,3),(-4,5),(-2,7),(7,7)

2006-10-27 12:35:29 · answer #5 · answered by Jorge. 2 · 1 0

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