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How do they count ?

2006-10-27 04:27:23 · 19 answers · asked by Arry Goo 2 in Science & Mathematics Mathematics

19 answers

Romal Numerals

I = 1. . . . . . .. .XXI = 21
II = 2. .. . . . . .XXII = 22
III = 3. . . . . . . .XXIII = 23
IV = 4. . . . . . . .XXIV = 24
V = 5. . . . . . . .XXV = 25
VI = 6. . . . . . . .XXVI = 26
VII = 7. .. . . . . . XXVII = 27
VIII = 8. . . . . . . .XXVIII = 28
IX = 9. . . . . . . .XXIX = 29
X = 10. . . . . . .XXX = 30
XI = 11. . . . . . .XXXI = 31
XII = 12.. . . . . . XXXII = 32
XIII = 13 . . . . . . . XXXIII = 33
XIV = 14. . . . . . .XXXIV = 34
XV = 15. . . . . . .XXXV = 35
XVI = 16. . . . . . .XXXVI = 36
XVII = 17. . . .. . .XXXVII = 37
XVIII = 18. . . . . . .XXXVIII = 38
XIX = 19. . . . . . .XXXIX = 39
XX = 20. . . . . . .XL = 40

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Click on the URL below for additioal information concerning Romal Numerals

www.legionxxiv.org/numerals

www.yourdictionary.com/crossword/romanums.html

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2006-10-27 05:45:01 · answer #1 · answered by SAMUEL D 7 · 0 1

The common roman numerals (up to 100) are: I=1, V=5, X=10, L=50 and C=100. It's easy to figure out how I, II, and III are 1, 2 and 3. For the rest, if the smaller number is on the left, it is subtracted, if it's on the right it's added. So to count to twenty: I, II, III, IV, V, VI, VII, VIII, IX, X, XI, XII, XIII, XIV, XV, XVI, XVII, XVIII, XIX, XX.

In addition to the complex method of numbering it's a pain to do math with this system. With no neat tens, hundreds and thousands places, the system does not break down easily. For these reasons the Roman numbering system has almost universally been replaced by the Arabic system.

2006-10-27 04:38:15 · answer #2 · answered by jaywalk57 2 · 0 1

They count in order from 1 to 5
Continuing 6 to 10 is
VI, VII, VIII, IX, X


It start with I = 1
V = 5
X = 10
There are never more than three III in a row. So for sometihng like 4 you have to do "five minus one" or IV

Hope this helps!

2006-10-27 04:28:27 · answer #3 · answered by IrishGuy85 2 · 2 1

Just count all the Super Bowls.

2006-10-27 04:29:30 · answer #4 · answered by Thanks for the Yahoo Jacket 7 · 2 0

I II III IV V VI VII VIII IX X XI XII XIII XIV XV XVI XVII XVIII XIX XX XXI

2006-10-27 04:33:36 · answer #5 · answered by viltc 2 · 1 1

Those are roman numerlas.
VI VII VIII IX X XI XII XIII XIV etc.

I = 1
V = 5
X = 10
L = 50
C = 100
D = 500
M = 1000

http://www.novaroma.org/via_romana/numbers.html
may help.

2006-10-27 04:30:43 · answer #6 · answered by LaxPlayer35 1 · 1 1

henry IV became the son of john of gaunt, duke of lancaster. richard II became the son the edward the black prince, who dies till now he might want to reign. richard II had no toddlers, and henry IV deposed richard and in all likelihood had him murdered, through being exiled to france for particularly many years. he also omitted the line of lionel of york, his uncle. this finally further about the wars of the roses between henry VI (lancaster) and richard duke of york.

2016-12-05 07:07:00 · answer #7 · answered by ? 4 · 0 0

I II III IV V VI VII VIII IX X XI XII XIII XIV XV XVI XVII XVIII IXX XX XXI XXII XXIII XXIV XXV XXVI XXVII XXVIII IXXX XXX XXXI XXXII XXXIII XXXIV XXXV XXXVI XXXVII XXXVIII IXXXX XXXX ...

L = 50
C = 100
M = 1000

2006-10-27 06:59:08 · answer #8 · answered by Jen 2 · 0 1

I=1
V=5
X=10
L=50
C=100
D=500
M=1000
NB:if a smaller roman numeral(in terms ot value eg.V=5) comes before a bigger one it's subtracted 4rm(IX=10-1=9) it but if a bigger num. comes first de smaller num. is added to it.(XI=10+1=11)

2006-10-27 04:48:05 · answer #9 · answered by Anonymous · 0 1

Yours is 1 - 5, continuing is Vl, Vll, Vlll, and lX, 6thru 10.

2006-10-27 04:47:39 · answer #10 · answered by Anonymous · 0 1

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