f(x)=-X^2(x^2-4)(x-5)?

Answer 1

You probably want the values of x for which the function f(x) becomes zero.

Then, x^2(x^2 - 4)(x - 5) = 0
So either x = 0 or x^2 - 4 = 0 or x - 5 = 0
Thus, either x = 0 or x = 5 or x^2 - 4 = 0

x^2 - 4 = 0 means (x + 2)(x - 2) = 0 i.e. either x = 2 or x = -2

Thus the function becomes 0 at x = -2, 0, 2, 5

You must specify the question exactly!

Answer 2

wat do u mean ? solve it or just expand it or just times the formula?

# f(x)=-x^2(x^2-4)(x-5)
f(x)=-x^2(x-2)(x+2)(x-5)
# f(x)=-x^2(x^3-5x^2-4x+20)
f(x)=-x^5+5x^4+4x^3-20x^2