If the larger of two consecutive integers is 7 greater than twice the smaller, how do I find the two integers?

Answer 1

Let them be x and x+1
given x+1(larger) = 7+ 2x(7 more than twice smaller)
solving x = -6

the 2 numbers are -6 and -5

Answer 2

An integer is a whole number. If seven is the greater of two consecutive integers (whole numbers) then six must be the smaller. Six, Seven and Eight are all consecutive whole numbers (Six is the smallest Eight is the largest).

greater than twice the smaller?

I assume your asking what is half of the smaller of the consecutive integers (six), which would of course be three.

Answer 3

smaller no=x
larger no=2x+7

larger no-smaller no=1
2x+7-x=1
x+7=1
x= -6
so the two consecutive nos are -6 & 2(-6)+7
so they are -6 & -5

Answer 4

Let the two consecutive integers be 'x' and 'x+1'
x+1 = 2x + 7 according to your question.
2x + 7 = x+1
2x = x + 1 -7
2x = x -6
2x - x = -6
x = -6
One integer is -6, the other is -6 +1 = -5
The two integers are -6 and -5

Answer 5

two consecutive with seven. 6 7 or 8 . Larger is 7 so that is only 6 & 7 half of six 3

xxB

Answer 6

let X, Y be the integers, in order, then,

Y=X+1
Y=2X+7

so, X+1=2X+7, and therefore,

X=-6 and so,
Y=-6+1= -5

Answer 7

if A, B are two numbers that are consecutive

A being Smaller than B

B = A + 1 --- 1
B = 2A + 7 --- 2
--------------- negate the 1 eq
0= A + 6

A = -6
B = -6 + 1
B = -5

Answer 8

let the larger be L and the smaller be S
the equations
L=7+2S
L-2S=7......(1)
L-S=1...... (2)
(2)-(1)
S=-6
substituting in (1)
L=-5
so the numbersare -6 and -5