The area of the top of a rectangular box is 324 in. squared, the area of the front of the box is 135 in.sq. and the area of the end is 60 in.sq. What is the volume of the box? THANK YOU
2006-10-26 17:23:36 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
SA = 2(lb + lh + bh)
V=lbh
lb = 324 ========> l = 324/b ..... (1)
lh = 135 ========> l = 135/h ..... (2)
bh = 60 ...... (3)
324/b = 135/h
135 b = 324 h
15 b = 36 h
From 3
15bh = 900
Thus 36h*h = 900
ie (6h)^2 = 30^2
6h = 30
h = 5
So b = 27 and l = 12
Thus V = 12 * 27 * 5
= 1620 in^2
Of course Peter!!! Much simpler as V^2 = lb * bh * lh!!!!!!! Well done!!!!!!! Very elegant
2006-10-26 17:36:06 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
it is easy,the answer is the square root of 324*135*135
so the volume is 2430.
if the end is 60,thne the correct is 1620
2006-10-27 00:29:38 · answer #2 · answered by peterwan1982 2 · 1⤊ 0⤋
V = LWH
LW = 324 in^2
LH = 135 in^2
HW = 60 in^2
H = 60/W
60L/W = 135
W = 60L/135
60L^2 = 135*324
L^2 = 135*324/60
L = 27
W = 12
H = 5
V = 1,620 in^3
2006-10-27 00:39:49 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋