assume you had a mixture of solid Na2CO3 and NaCl. how could you show the presence of both carbonate and chlor

Answer 1

Dissolve the mixture in water. Then, add a little silver nitrate. Silver ions precipitate with chloride ions to form silver chloride. Then you could add some acid, like a little nitric acid. The carbonate ions will react with the protons to form carbonic acid, which will decompose into CO2 gas, and make bubbles.

Answer 2

To test for CO3 (2-) ions, simply add an acid then you'll see bubbles of CO2.
Na2CO3 + 2HCl --> 2NaCl + H2O + CO2

To test for Cl (-) ions, simply add Copper, Silver or Lead salt. The precipitate formed when adding this is showing the presence of Cl (-)
2NaCl + CuSO4 --> CuCl2 + Na2SO4

Hope it helps

peace
vixklen

Answer 3

Solid Na2co3