An AM radio station broadcasts at 1540 kHz, and its FM partner broadcasts at 100.5 MHz. Calculate and compare the energy of photons emitted by these radio stations.
AM___________J
FM___________J
EFM/EAM_______________
I got 194805.19 for AM, and 2.985 for FM..but couldnt fine EFM/EAM! Are these right?? if not..how can I fix it!?!
2006-10-26 16:52:10 · 1 answers · asked by lsubetty 2 in Education & Reference ➔ Homework Help
The photon energy is E=h*f, where f=frequency, and h = Planck's constant 6.6261*10^-34 J*sec. This comes out 10.204*10^-28 joules for the AM station (1.54*10^6 sec^-1 * 6.626*10^-34 J*sec). For the FM, f=1.005*10^8 sec^-1, which gives 6.659*10^26 joules. Are you sure you have the right value for Planck's constant> See http://en.wikipedia.org/wiki/Planck_constant
The energy ratio is then is the same as the frequency ratio, 100.5/1.540 = 65.26
2006-10-26 18:58:38 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋