Integral Calculus.... ò (1/x)[ln (x)^3] dx =?

Answer 1

perform a substitution
u=lnx du=(1/x)dx

ln(x^3)=3lnx

Integral[(1/x)(3lnx)dx]= Integral[(3u)du]
=(3u^2)/2= 3[(lnx)^2]/2 + C