I heard some rumor the other day that Charles Manson is suppose to get released some time next year. Is this really true?
2006-10-26 15:56:49 · 11 answers · asked by Anonymous in News & Events ➔ Other - News & Events
I couldn't find anything to support that rumor. I hope he stays in prison until he's dead. He killed too many people to have served enough time for all the murders. He's one sick SOB.
2006-10-26 16:08:59 · answer #1 · answered by Belle 6 · 1⤊ 0⤋
Manson has been up for parole many times and always denied. i think now he is at the point where he will never be paroled and that is for his own safety. Too many people would like to go down in the history books as the one who killed him.
2006-10-26 17:42:58 · answer #2 · answered by livingstonseagull43 3 · 2⤊ 0⤋
Yes, Manson is up for parole in 2007, although he was also eligible in 2002 and denied.
2006-10-26 16:45:44 · answer #3 · answered by rk 2 · 2⤊ 0⤋
I highly doubt he will ever see the light of day again.If he does get paroled,all I can say is there is something seriously wrong with our judicial system.The man is a menace and thinks he is Jesus Christ,some serious mental issues there.
2006-10-27 03:27:45 · answer #4 · answered by stellablue1959 5 · 1⤊ 0⤋
I don't see that happening.
He may be up for parole .. but he has been before, and it was (Thank you, Lord) denied.
The man is a menace...and will always be a menace to society.
Ditto Tex Watson, his partner in those horrendous crimes.
2006-10-26 18:19:18 · answer #5 · answered by ax2usn 4 · 1⤊ 0⤋
Invite him over for Tea and Biscotti ! Then show him the Nice Big Hole I've been digging since he moved in !
2016-05-21 23:51:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋
No, he will never get out of prison.
2006-10-26 16:57:20 · answer #7 · answered by fatboysdaddy 7 · 1⤊ 0⤋
I sure hope not.
2006-10-26 16:07:31 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Aboslutely no way.
2006-10-26 16:07:11 · answer #9 · answered by Laurie H 3 · 0⤊ 0⤋
I sure hope not..
2006-10-26 16:48:40 · answer #10 · answered by Nette 2 · 1⤊ 0⤋