Integral Calculus.... ò (6e^6/x)(x^-2) dx =?

2006-10-26 15:44:45 · 2 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

Let u=6/x. Then du = -6/x^2, and you have

integral of -e^u du = -e^u + C = -e^(6/x) + C

2006-10-26 15:47:38 · answer #1 · answered by James L 5 · 1⤊ 0⤋

ewwwwww.....geez i forgot how to do that and i did that stuff last year x_x sorry

2006-10-26 22:47:59 · answer #2 · answered by ssj4gokugirl 2 · 0⤊ 0⤋

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