Calculus, Integral Problem....?

1 ⤊

integral

3
ò (4x - x3 ) dx =
-3

2006-10-26 15:32:53 · 3 answers · asked by Olivia 4 in Science & Mathematics ➔ Mathematics

you are correct

x^3

2006-10-26 15:36:37 · update #1

integral from -3 to 3 of 4x -x^3 dx
= 4x^2 /2 -x^4 /4 evalutated from -3 to 3
=2(3)^2 - (3)^4/4
=0

2006-10-27 03:33:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋

I assume you mean 4x - x^3?

This is an odd function, integrated on an interval of the form [-a,a], so the integral is zero.

2006-10-26 22:35:13 · answer #2 · answered by James L 5 · 1⤊ 0⤋

Zero.

It's an odd function so the definite integral on the negative side offsets the definite integral on the positive side.

2006-10-26 22:38:49 · answer #3 · answered by just♪wondering 7 · 0⤊ 0⤋