please help
2006-10-26 15:10:35 · 5 answers · asked by sir lancelot 1 in Science & Mathematics ➔ Mathematics
Divide the leading terms: 6a^2 / 2a = 3a. That is the first term in the quotient.
6a^2 - 13a - 18 - 3a(2a+1) = 6a^2-13a-18 - 6a^2 - 3a
= -16a - 18.
Divide the leading terms again: -16a/2a = -8, so that is the second and last term in the quotient.
-16a-18 - (-8)(2a+1) = -16a - 18 + 16a + 8 = -10, which is the remainder.
(6a^2 - 13a - 18) / (2a+1) = (3a-8) - 10/(2a+1).
2006-10-26 15:15:15 · answer #1 · answered by James L 5 · 0⤊ 0⤋
3a -18 15a/2a+1
2006-10-26 22:19:11 · answer #2 · answered by nerdy_pearlita 3 · 0⤊ 0⤋
Use synthetic division (look it up on line).
Hint: It won't come out even. (There will be a remainder.)
2006-10-26 22:12:57 · answer #3 · answered by actuator 5 · 0⤊ 0⤋
ill give you a hint, factor out the top
then cancel!
2006-10-26 22:11:58 · answer #4 · answered by sur2124 4 · 0⤊ 0⤋
i hope you are loooking for the answer because it is 31
2006-10-26 22:13:23 · answer #5 · answered by sherie f 1 · 0⤊ 0⤋