how does the size of the force of the cannon on the cannonball compare with the force of the cannonball on the connon? how does the acceleration of the cannon compare with that of the cannonball? Defend your answer.
2006-10-26 15:01:44 · 7 answers · asked by water yu 3 in Science & Mathematics ➔ Physics
Physics my friend, this goes right back to newtons laws that any action will have an opposite and equal reaction. In this case the canon out wights the ball by well say 100X this means that all the force will be exerted forwarded towered the opening of the canon, like water gas will take the route of least resistant. This is also why when a canon is fired it will only recoil 100Th the weight of the canon. This means that the canon ball is receiving the brunt of the force this can acutely warp the ball if there is to much force. As for the canon, if the gases expand and did not release the ball the pressure would rupture the canon at it's weakest point usually the welding if this did not happen it would be like a giant hand grenade going off. Hope this helps.
2006-10-26 15:12:24 · answer #1 · answered by matt v 3 · 0⤊ 0⤋
Everyone is giving you basically the same answer, except some remember that the cannon is attached to the earth and some don't.
If the cannon is solidly attached to the earth (e.g., bolted to a concrete base), then it's acceleration will be negligible (proportional to the mass of the cannonball divided by the mass of the earth).
2006-10-26 22:44:41 · answer #2 · answered by actuator 5 · 0⤊ 0⤋
well, Force = mass*acceleration. For the case of the cannon firing these 2 forces are considered equal and opposite. that means that you will have the equation:
mass(cannonball)*acceleration(cannonball) = mass(cannon)*acceleration(cannon)
rearranging you would get:
acceleration(cannon) = [mass(cannonball)/mass(cannon)] * accleration(cannonball)
since the mass of the cannon is much larger than that of the cannonball, the acceleration of the cannon will be quite small compared to that of the cannonball.
2006-10-26 22:07:03 · answer #3 · answered by j 3 · 0⤊ 0⤋
Newton's third law says the forces will be equal but because the cannon has more mass Newton'e 2nd Law says the cannon has less acceleration
2006-10-26 22:04:32 · answer #4 · answered by jwlh_228 2 · 0⤊ 0⤋
F = ma
every action has an equal and opposite re-action.
the force on the ball and the cannon are equal and opposite.
the acceleration of the ball is greater than the cannon because the mass of the ball is less than that of the cannon.
2006-10-26 22:09:38 · answer #5 · answered by DanE 7 · 0⤊ 0⤋
The forces are equal by newton's 3rd law
The acceleration of the canon (assuming it isn't attached to the earth) compared to the a of the ball is Mb/Mc by Newton's 2nd law
2006-10-26 22:08:36 · answer #6 · answered by Steve 7 · 0⤊ 0⤋
f=ma, and the force is equal on both but in opposite directions. So (let c represent cannon and b represent ball), mcxac=mbxab and the acceleration of the cannon ac=(mb/mc)xab.
2006-10-26 22:12:53 · answer #7 · answered by Anonymous · 0⤊ 0⤋