Consecutive Integer Problem?

Question

Three times the greatest of 3 consecutive even integers exceeds twice the least by 38. Find the integers.
Can you also tell me how you solved it.
Thanks.
:]
<3Johnny.

Answer 1

Let them be x , x+2 and x +4
3 times the greatest = 3(x+4)
twice the least = 2x
so 2x+38 = 3x + 12

x = 26
numbers are 26,28,30

Answer 2

Let the even integers be a, a+2, a+4
3 times the largest is 3(a+4) and 2 times the smallest is 2(a)
3(a + 4) - 2(a ) = 38
3a + 12 - 2a = 38
a + 12 = 38
a = 38 - 12
a = 26
To find the integers you need to substitute the number 26 in to each of the terms and you will arrive at these numbers 26, 28, 30

Answer 3

Let k be half the smallest, thesmallest integer is then 2k, this ensures the smallest is even Then the next two conscutive even integers are 2k+2 and 2k+4. The greatest is 2k+4. Three times the greatest is 3*(2k+4). This is more than 2*2k by 38; therefore 3*(2k+4)=38+4k; solve for k, and you get 2k, 2k+2 and 2k+4 as the three integers.

After several edits, I got this right. Apparently charissa doesn't know what even means. The answer is 26,28,30. Check it out: 3*30 = 90;
38 +2*26 = 28+52 = 90.

Answer 4

Let x,y,z be the even integers, in increasing order.

Then y=x+2, and z=x+4.

Also, 3z = 2x + 38, so 3(x+4) = 2x + 38, or 3x+12=2x+38. Therefore x=26, and y=28, and z=30.

Answer 5

x is the least

x*2 + 38 = (x+2)*3

solve it.

Answer 6

these are ALLLLLL wrong! apparently these people don't know what consecutive means!!!

the answer is: 31, 32, and 33.

how i found the answer: guess and check. i doubled the first number and subtracted it from the third number times 3.

Answer 7

3(x+4)=2x+38
26, 28, 30

Answer 8

dude

Answer 9

ok